- Sep 30, 2018
- 102
- 70
Hi guys,
I have no more issue with this case but I don't understand the logic of operation.
How can you explain that after the jumpLabel01 is done, callLabel01 execute again the call callLabel02 ?
There is probably a logic answer but not for my little brain !!!
I have no more issue with this case but I don't understand the logic of operation.
Python:
default cpt = 0
label callLabel01:
currentSpeaker "Begin First Call without return in code"
call callLabel02
currentSpeaker "End First Call without return in code"
label callLabel02:
currentSpeaker "Begin Second Call without return in code"
jump jumpLabel01
currentSpeaker "End Second Call without return in code"
label jumpLabel01:
$ cpt += 1
currentSpeaker "Jump, cpt = [cpt]"
return
There is probably a logic answer but not for my little brain !!!
Last edited: