- Apr 11, 2020
- 322
- 607
That's an interesting math problem actually.DOnt think Tinkerer will go for big orgy due every girl is a 2x factor, a pregnant and non pregnant version due its big kink of the game. so if he dont deliver it than people will be mad at him. its not the coding but the rendering of it all that takes ages.
Q: We have 5 girls in an orgy, every girl can be or not to be pregnant. How many renders Tinkerer needs per image to cover all possible combination?
A:
No-one is pregnant. Obviously 1.
1 girl is pregnant. That's an easy one as well - 5.
2 girls are pregnant. A bit more complicated. 5!/(5-2)! 2! = 5!/3! 2! = 10
3 girls are pregnant. Basically the same as previous. 5!/(5-3)! 3! = 5!/2! 3! = 10
4 girls are pregnant. 5!/(5-4)! 4! = 5!/1! 4! = 5
All girls are pregnant. 1 again ofc.
Final answer: Tinkerer need 1+5+10+10+5+1 = 32 renders per image
If you add 3rd factor (a-bit-pregnant for example) it's getting wayyyy more complicated ofc. But if you add Maghda the answer will always be 0. At least for me.
Somehow I doubt they will ever ask that question in math class.