BlandChili

Well-Known Member
Dec 15, 2020
1,840
3,969
This is the best portrayal of Holly in the entire game. Lena+Ivy lessons was useful.

View attachment 3577305
Yes, my Ian called her hot but it seems she's locked in with Lena right now, so I am probably safe to play Mr. Flirts-a-lot with Ian without fearing losing her for Lena. :ROFLMAO:

Hmm looks like Lena gets two different summer looks, depending on her Lust variable:

View attachment 3577306 View attachment 3577307

The new one kicks in with Lust of 8+ (if it's 9 or more she adds a choker to it)
Yes, I had outfit 2, don't remember if she had the choker.
Quite pleased, that purple top is much better than the striped one. :giggle:
 

Geralt From Rivia

Forum Fanatic
Jun 15, 2022
5,115
30,514
Yes, my Ian called her hot but it seems she's locked in with Lena right now, so I am probably safe to play Mr. Flirts-a-lot with Ian without fearing losing her for Lena. :ROFLMAO:


Yes, I had outfit 2, don't remember if she had the choker.
Quite pleased, that purple top is much better than the striped one. :giggle:
Never developed Lena/Holly, but they kissed and now Holly have feelings to Lena.
I'm playing this game too chaotic.
 

ffive

Forum Fanatic
Jun 19, 2022
4,922
10,620
PilotLara one more thing: There is currently what i'd consider a serious issue with Lena/Axel path. Specifically, if the player gets onto this path by having sex with Axel in Chapter 9, there's no ability to stop it, even though the game seems to think there is and provides options to do so.

The (two-fold) problem is specifically with Lena's will points: having sex with Axel in Ch.9 sets Lena's will points to 0. From this moment onwards Lena can only gather 1 will point (by writing song in Chapter 11) but to shut down Axel's path the game requires Lena to burn 2 points in single sequence
Python:
        "{image=icon_will.webp}I have to go" if lena_will > 0:
            label v12rejectaxel:
                $ lena_axel_desire_over = True
                call willdown from _call_willdown_69
//...
            if lena_axel_desire:
                l "I think we said everything that needed to be said..."
                "I felt Axel's hand resting on my hip. He was so close to me."
                x "Are you sure?"
                "I looked into Axel's eyes. Could I ever see him as just a friend?"
                menu:
                    "{image=icon_love.webp}Kiss Axel":
//...
                    "{image=icon_will.webp}Get on the train" if lena_will > 0:
                        call willdown from _call_willdown_70
//...
On top of this, Lena potentially needs third will point to spend shortly before this scene, if she is in relationship with Ian and wants to stop her cheating (the cheating flag is set by having sex with Axel)

Not only Lena can't get this many points in this short timespan, the game doesn't even physically let her hold this many, because the max number she can store is 2.

I'd suggest adding a few more instances of getting will points for Lena in Ch.10-11, especially since there can be other ways the player might want to spend them (like for a threesome with Ian/Louise) And either increase the limit to 3, or rework the cost of actions for Lena in Ch.12
 
Last edited:

yilkin

dl.rpdl.net
Donor
Feb 23, 2023
8,718
4,717
OurRedString-CH12Alpha
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Andrea9999

Active Member
Nov 9, 2022
526
720
Being Dominant, and being abusive are not mutually exclusive things. It's possible to be both abusive and Dominant. It's possible to be Dominant and not abusive. It's possible to be neither dominant nor abusive. It's possible to be abusive but not Dominant. They are independent unrelated variables.
Deepest, and most abject and tearful apologies....but you would need to construct and analyze a contingency table to see if these variables are really and truly independent after taking enough data. It is possible, for example, that the probability of a person being abusive, given that they are dominant is higher than the probability of being abusive given that they are not dominant. It might be interesting to also bring submissiveness into the mix. In order for the variables to be completely independent we would need, where D=dominant and A=abusive:
P(D)=P(D|A) and P(A)=P(A|D), that is, the probability of a person being dominant = the probability of a person being dominant, given that they are abusive. And the probability of a person being abusive = the probability of a person being abusive, given that they are dominant.
 
4.60 star(s) 307 Votes