- Oct 11, 2023
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- 1,089
Well then you did something wrong, because there is sex with justine.Nope blueballs
Well then you did something wrong, because there is sex with justine.Nope blueballs
How did you get that scene where he slides her bikini to the side?I got Jen giving MC a lapdance and he is wearing shorts, but he moves the bikini to her side exposing her pussy and she is dry humping MC for two minutes than she gets off MC and husband sees Jens pussy hanging out and goes ballistic, and he says "what do you two get up to when I'm not here" then they both go to bed and MC shags his girlfriend in bedroom.
More dom points and less brother point.How did you get that scene where he slides her bikini to the side?
Your behavior towards your brother and his wife will lead the way to 4 major paths, each with several endings Dom Love, L D, D D, L L
Some events have 4 variations, some have 3, some possibly only 2, but the 4 variations or paths seem to be based on 2 main conditions: whether you have more love or dom points and whether you have more brother or enemy points.I had previously divided my saves into 3 paths (D > L; L > D, L = D), so can you explain the 4th to me?
if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint:
jump d11lapdance_lo_bro
if Lovepoint >= Dompoint and Brotherpoint < Enemypoint:
jump d11lapdance_lo_ene
if Lovepoint < Dompoint and Brotherpoint >= Enemypoint:
jump d11lapdance_dom_bro
if Lovepoint < Dompoint and Brotherpoint < Enemypoint:
jump d11lapdance_dom_ene
if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint:
jump d11poolend_lo_bro
if Lovepoint < Dompoint and Brotherpoint >= Enemypoint:
jump d11poolend_dom_bro
if Lovepoint >= Dompoint and Brotherpoint < Enemypoint:
jump d11poolend_lo_ene
Lovepoint == Dompoint
and the same goes for Brotherpoint == Enemypoint
. Keeping either of these points strictly equal seems to be pointless (pun intended).No. He sticks around, no matter the path.Does the brother leave the pool before the lap dance? And how to reach that. Thank you.
Thank you. Yes Jennifer left twice angry and twice happily, depends on the points.No. He sticks around, no matter the path.
Only on the "dom enemy" path the lap dance will end the "party" - Jen leaves after the scene and brother follows her.
Other paths last longer.
Some events have 4 variations, some have 3, some possibly only 2, but the 4 variations or paths seem to be based on 2 main conditions: whether you have more love or dom points and whether you have more brother or enemy points.
Combining these two conditions you get 4 different combinations maximum.
Python:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint: jump d11lapdance_lo_bro if Lovepoint >= Dompoint and Brotherpoint < Enemypoint: jump d11lapdance_lo_ene if Lovepoint < Dompoint and Brotherpoint >= Enemypoint: jump d11lapdance_dom_bro if Lovepoint < Dompoint and Brotherpoint < Enemypoint: jump d11lapdance_dom_ene
BTW, there seems to be currently zero conditions wherePython:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint: jump d11poolend_lo_bro if Lovepoint < Dompoint and Brotherpoint >= Enemypoint: jump d11poolend_dom_bro if Lovepoint >= Dompoint and Brotherpoint < Enemypoint: jump d11poolend_lo_ene
Lovepoint == Dompoint
and the same goes forBrotherpoint == Enemypoint
. Keeping either of these points strictly equal seems to be pointless (pun intended).
Actually, the first line does have the condition whereSome events have 4 variations, some have 3, some possibly only 2, but the 4 variations or paths seem to be based on 2 main conditions: whether you have more love or dom points and whether you have more brother or enemy points.
Combining these two conditions you get 4 different combinations maximum.
Python:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint: jump d11lapdance_lo_bro if Lovepoint >= Dompoint and Brotherpoint < Enemypoint: jump d11lapdance_lo_ene if Lovepoint < Dompoint and Brotherpoint >= Enemypoint: jump d11lapdance_dom_bro if Lovepoint < Dompoint and Brotherpoint < Enemypoint: jump d11lapdance_dom_ene
BTW, there seems to be currently zero conditions wherePython:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint: jump d11poolend_lo_bro if Lovepoint < Dompoint and Brotherpoint >= Enemypoint: jump d11poolend_dom_bro if Lovepoint >= Dompoint and Brotherpoint < Enemypoint: jump d11poolend_lo_ene
Lovepoint == Dompoint
and the same goes forBrotherpoint == Enemypoint
. Keeping either of these points strictly equal seems to be pointless (pun intended).
Lovepoint == Dompoint
and for Brotherpoint == Enemypoint
. In the line you posted if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint
It includes the condition of points being equal. This is not the same thing as an exclusive condition of the points being equal. Anyone who knows the basics of programming or math knows this without further explanation.Actually, the first line does have the condition whereLovepoint == Dompoint
and forBrotherpoint == Enemypoint
. In the line you posted
THat condition is satisfied if either one are equal.Python:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint
Good point.
What exactly is your point stating the obvious? However, this is only one of the 4 possible combinations of values when the statement is TrueTHat condition is satisfied if either one are equal.Python:if Lovepoint >= Dompoint and Brotherpoint >= Enemypoint
Good point.
No, not trying to troll.It includes the condition of points being equal. This is not the same thing as an exclusive condition of the points being equal. Anyone who knows the basics of programming or math knows this without further explanation.
My conclusion was that there is no reason to hold onto a path where points are exactly equal. It's enough to have two paths for either pair of variables - one where there is less Lovepoints and one where there is more or equal amount of Lovepoints. The same goes for Brotherpoints.
You either know exactly what I'm talking about and are just wasting my time trolling or you don't know what you are talking about and I'm not going to waste my time teaching you the basics.
What exactly is your point stating the obvious? However, this is only one of the 4 possible combinations of values when the statement is True
Correct, no point in keeping them equal... and now I see that there was a pun too.Keeping either of these points strictly equal seems to be pointless (pun intended).